The equation of a circle is (x+7) to the second power + (y-13) to the second power=196 .

What is the center of the circle?

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Instead of writing " (x+7) to the second power", you can write " (x+7) ^2" which is more efficient.

The equation given to us is

(x+7) ^2 + (y-13) ^2 = 196

which is the same as

(x - (-7)) ^2 + (y-13) ^2 = 14^2

and that equation is in the form

(x-h) ^2 + (y-k) ^2 = r^2

We can see that

h = - 7

k = 13

r = 14

This means (h, k) = (-7,13)

The center is (-7,13)