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20 November, 09:04

If the resistance of one component of a series circuit is 3+j5 ohms, and the resistance of the second component of the circuit is 5-j8 ohms, and the resistance of the third component of the circuit is 6+j4 ohms, what is the total resistance in the circuit?

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  1. 20 November, 09:38
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    In a series circuit, the total resistance is obtained by R1+R2+R3+Rn where R is the resistance of each component

    We have

    R1 = 3+j5

    R2 = 5-J8

    R3 = 6+J4

    Hence the total resistance, RT, is given

    RT = 3 + j5 + 5 - j8 + 6 + j4 = 14+j1
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