The length of rectangle is 6 feet greater than the width. the perimeter is 40 ft. find the dimensions of the rectangle.

P=2 (L+W)

if L is 6 great than W

L=6+W

and P=40

subsitute 40 for P and 6+W for l

40=2 (6+W+W)

40=2 (6+2W)

divide both sides by 2

20=6+2W

minus 6 both sides

14=2W

divide both sides by 2

7=W

W=7

sub back

L=6+W

L=6+7

L=13

the rectangle has a length of 13ft and width of 7ft