What are the intercepts of 7x+2y-14z=56

A. (8,0,0) (0,-28,0) (0,0,-4)

B. (8,0,0) (0,28,0) (0,0,-4)

C. (8,0,0) (0,28,0) (0,0,4)

D. (8,0,0) (0,-28,0) (0,0,4)

Since the equation is in 3 variables, there will be 3 intercepts:

1) x-intercept

Where y and z coordinate are zero.

So, we can say

7x + 2 (0) - 14 (0) = 56

So, x = 8 is the x-intercept

2) y-intercept

where x and z coordinate are zero

So, we can write

7 (0) + 2y - 14 (0) = 56

So, y = 28 is the y-intercept

3) z-intercept

where x and y coordinates are zero

So, we can write

7 (0) + 2 (0) - 14z=56

So, z=-4 is the z intercept

Therefore, the correct answer to this question is option B