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9 August, 15:17

What is the sum of this geometric series? 16+32 + ... + 256

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  1. 9 August, 16:12
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    U1 = a = 16

    r = 32/16 = 2

    Un = 256

    Un = a. r^n-1

    256 = 16.2^n-1

    2^n-1 = 256/16

    2^n-1 = 16

    2^n-1 = 2^4

    n-1 = 4

    n = 5

    Sn = a (r^n - 1) / r-1

    S5 = 16 (2^5 - 1) / 2-1

    S5 = 16 (31)

    S5 = 496
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