What is the domain of y=4√4x+2

Y = ⁴√ (4x + 2)

Since the index is even, the radicand has to be greater than or equal to zero. Take whatever is under the radical sign and set it ≥ zero and solve. This will be the domain of the function.

4x + 2 ≥ 0

Subtract 2 from both sides

4x ≥ - 2

Divide both sides by 4

x ≥ - 2/4

x ≥ - 1/2

A. all real numbers is the answer