The number of pollinated flowers as a function of time in days can be represented by the function. f (x) = (3) x2 What is the average increase in the number of flowers pollinated per day between days 4 and 10?

Enter your answer in the box.

Actually the answer is 39, I just took the test. If you are in K12 OLS, the answer is 39

So in this case f (x) is number of pollinated flowers and x is the days. First you will need to determine the number of flowers pollinated at days 4 and 10 and the days in between.

f (4) = 3 (4^2) = 3*16 = 48

f (5) = 3 (5^2) = 3*25 = 75

f (6) = 3 (6^2) = 3*36=108

f (7) = 3 (7^2) = 3*49=147

f (8) = 3 (8^2) = 3*64=192

f (9) = 3 (9^2) = 3*81=243

f (10) = 3 (10^2) = 3*100=300

Now we need to find the average increase, so that will be the average of the differences between days

[ (75-48) + (108-75) + (147-108) + (192-147) + (243-192) + (300-243) ]/6

= (27+33+39+45+51+57) / 6=42