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26 August, 04:13

A, b, c are positive integers. a:b = 3:8 b:c = 6:11 work out the smallest possible value of a+b+c

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  1. 26 August, 04:37
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    Work out the a:b:c ratio.

    b is present in both ratios, find first the LCM of 8 and 6, which is 24.

    Multiply a:b=3:8 by 3 to get a:b=9:24

    Similarly, multiply b:c=6:11 by 4 to get b:c=24:44

    Then we conclude

    a:b:c=9:24:44

    Since there is no common factor among the three numbers, this is the simplest ratio possible.

    If a, b and c are integers, the smallest values for a, b and c are 9,24,44.

    Add up the three numbers to get the least value of a+b+c.
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