Find the exact solutions of sin (2x) - sin (x) = 0 in the interval [0, 2pi)

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Mathematics

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27 March, 21:29

Find the exact solutions of sin (2x) - sin (x) = 0 in the interval [0, 2pi)

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Giovanna Parks · Answer 1

Sin (2x) - sin (x) = 0

2sin (x) * cos (x) - sin (x) = 0

sin (x) * (2cos (x) - 1) = 0

Sin (x) = 0 = > x [PiK]

Cos (x) = 1/2 = > x[Pi/3 + (2PiK/3)

K=0 x=0

K=1 x=Pi

K=2 x=5Pi/3

So the answer is 0, Pi, 5Pi/3