A combined total of $49,000 is invested in two bonds that pay 2% and 6.5%simple interest. The annual interest is $2,5100. How much is invested in each bond?

Let x is the bond pay 2% and y is the pay 6.5%

x + y = 49,000 so x = 49,000 - y

0.02x + 0.065y = 2,510

substitute x = 49,000 - y into 0.02x + 0.065y = 2,510

0.02x + 0.065y = 2,510

0.02 (49,000 - y) + 0.065y = 2,510

980 - 0.02y + 0.065y = 2,510

0.045y = 1,530

y = 34,000

x = 49,000 - y = 49,000 - 34,000 = 15,000

answer

invested $34,000 in the bond that pays 6.5% rate and $15,000 in bond that pays 2% rate