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4 June, 09:06

The equation for the circle is:

x2+y2+14x+10y-7=0.

What is the center of the circle?

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Answers (1)
  1. 4 June, 10:56
    0
    Use completion of sq method

    x^2+y^2+14x+10y-7=0

    (x+7) ^2 + (y+5) ^2=7+49+25

    (x+7) ^2 + (y+5) ^2=81

    so centre is (-7,-5) radius is9
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