The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40cm. the lift raises a load of 15,000N.

a) Determine the force that must be applied to the small piston.

b) Determine the pressure applied to the fluid in the lift.

We are given with two dimaters of piston 8 cm and 40 cm while the load is equivalent to 15000N. We are asked to determine the force applied to the small piston. Pressure is equal to force per unit area. In a, 15,000 N / 40^2 cm2 = F2 / 8^2cm2; F2 is equal to 600 N. In b, pressure is equal to 9.375 Pa