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18 June, 21:51

How to find the values of the six trigonometric functions for 180?

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  1. 18 June, 23:58
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    I like to imagine a triangle in place of the negative x axis of the unit circle where the opposite side = 0, the adjacent is - 1 and the hypotenuse = 1.

    so sin 180 = 0/1 = 0, cos 180 = - 1/1 = - 1 and tan 180 = - 0/-1 = 0.

    Then the other ratios are csc is 1/0 = indeterminate, sec = 1/-1 = - 1 and cot is indeterminate.
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