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6 July, 08:01

What are the focus and directrix of the parabola with the given equation x=-1/8y^2

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  1. 6 July, 08:43
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    X=-1/8y^2

    If the Vertex is at the origin: V = (h, k) = (0,0) →h=0, k=0

    y^2=4px

    (-8) (x=-1/8y^2)

    -8x=y^2

    y^2=-8x

    4p=-8

    Solving for p:

    4p/4=-8/4

    p=-2<0 (negative) →The parabola opens to the left

    Focus: F = (p, 0) →F = (-2,0)

    Drectrix: x=-p = - (-2) →Directrix: x=2

    Answers:

    Focus = (-2,0)

    Directrix: x=2
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