How much metal do you need to make a can that is 1 1/8 feet tall and has radius of 4 inches

You need 3,081.125 lbs of metal (iron) to make a can that is 1 1/8 feet tall and has a radius of 4 inches assuming that iron is the type of metal used for creating the can. This problem can be solved by using the tube volume formula which described as volume = phi*radius^2*height and the density formula which described as Density = mass/volume. The volume of the can is 0.3925 ft^3 and the density of an iron is 490 lbs/ft^3.