A bag contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.

If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red?

The simplified probability would be 12/91.

There are 4 green jelly beans out of a total of 14 jelly beans. The probability for the first bean would be 4/14.

Once the first jelly bean is removed, the probability that the second jelly bean would be red is 6/13 (the denominator decreases by 1 because of the first jelly bean that did not get put back).

Together the probability is (4/14) (6/13) = 24/182, which then simplifies to 12/91.