In the equation f (x) = x²+2x+3, there are 2 root.

true or false?

This is a equation:

ax²+bx+c=0

If you want the number of roots in any equation:

you only have to do this operation.

b²-4ac

if b²-4ac>0 you have two roots.

if b²-4ac=0 you have one root

if b²-4a<0 you don't have any real root.

in this case:

x²+2x+3=0

b²-4ac=2²-4 (1) (3) = 4-12=-8<0; then you don't have any real root.

answer. false