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7 January, 06:56

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are 20 and 2500, respectively.

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  1. 7 January, 08:49
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    Given that the 2nd and 5th term of a geometric sequence is 20 and 2500, the formula will be obtained as follows.

    The formula for geometric sequence is given by:

    nth=ar^ (n-1)

    where:

    a=1st term

    r=common ratio

    n=nth term

    thus the 2nd term is:

    20=ar^ (2-1)

    20=ar ... i

    the 5th term is:

    2500=ar^ (5-1)

    2500=ar^4 ... ii

    from i

    a=20/r

    from ii

    a=2500/r^4

    therefore:

    20/r=2500/r^4

    multiplying through by r^4 we get:

    20r^3=2500

    dividing both sides by 20 we get:

    r^3=125

    hence;

    r=5

    substituting the value of r in i we get:

    20=ar

    20=5a

    thus;

    a=4

    the formula for the sequence will therefore be:

    nth=ar^ (n-1)

    nth=4*5^ (n-1)
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