A church has 10 bells in its bell tower. before each church service 3 bells are rung in sequence. no bell is rung more than once. how many sequences are there?

To solve this problem you must apply the proccedure shown below:

1. You must apply the following Permutation formula:

nPr=n! / (n-r) !

Where n=8 and r=3

2. Therefore, you have:

n!=8!=8x7x6x5x4x3x2x1=40320

(n-r) ! = (8-3) !=5!=5x4x3x2x1=120

3. Then, when you substitute this values into the formula shown above, you obtain:

nPr=n! / (n-r) !

nPr=40320/120=336

4. Therefore, as you can see, the answer is: 336