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17 November, 02:22

Suppose a certain traffic light shows a red light for 42 seconds, a green light for 45 seconds, and a yellow light for 5 seconds. each day you look at this light at a randomly chosen instant. what is the probability you see a red light five days in a row?

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  1. 17 November, 06:01
    0
    Red light time = 42 seconds

    Green light time = 45 seconds

    Yellow light time = 5 seconds

    Total Time of all lights i (Red Light time + Green light time + Yellow light time)

    = 42 + 45 + 5 = 92 seconds

    Probability to see Red light in a day

    P (Red) = (Red light time) / (Total time of all lights)

    Probability to see Red light 5 days in a row

    P (Red) = (Red light time) ^5 / (Total time of all lights) ^5

    P (Red) = (42) ⁵ / (92) ⁵

    P (Red) = 0.01689

    Probability to see Red light 5 days in a row = 1.689%
  2. 17 November, 06:17
    0
    The time of a red light = 42 seconds

    The time of a green light = 45 seconds

    The time of a yellow light = 5 seconds

    so,

    All times = 42 + 45 + 5 = 92 seconds

    Then

    The probability to see a red light in one day = P (red) = (The time of a red light) : (all tmes)

    So, P (red) = 42/95

    And

    The probability to see a red light in five days = {P (red) }⁵ = (42/95) ⁵

    = 0.01689

    = 1.689 %
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