The frequency of A4 is 440.00 Hz.

what is the frequency of A6, which is two octaves above A4?

The formula for getting the unknown frequecy is given by, (2∧n) * f.

Where n ⇒the number of octavos above A4 and

f ⇒the given frequency

So, the frequency of A6 is calculated as follows.

Frequency = (2∧2) * 440.00

= 1760.00 Hz

To solve this problem you must apply the proccedure shown below:

1. You have the following information given in the problem above: The frequency of A4 is 440.00 Hz.

2. So, you must apply the following formula to calculate the frequency of A6, which is two octaves above:

(2 ^n) f

Where n is the octaves above and f is the known frequency.

3. Therefore, you have:

A6 = (2^n) f

A6 = (2^2) (440.00 Hz)

A6=1760 Hz

Therefore, the answer is: A6=1760 Hz.