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Yesterday, 21:30

A car completes a journey at an average speed of 40km/h. At what speed must it travel on the return journey if the average speed for the complete journey is 60km/h?

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  1. Yesterday, 23:04
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    The distance, s = 40t₁ where t₁ is the time to complete the outward journey.

    The same distance = vt₂ where t₂ is the time to complete the return journey at speed v.

    For the whole journey, 2s=60 (t₁+t₂). Therefore s=30 (t₁+t₂) = 40t₁=vt₂.

    30t₁+30t₂=40t₁, 10t₁=30t₂, t₁=3t₂, so s=120t₂=vt₂ and v=120kph.
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