How many solutions does the system 3x-y=6

3x+y=6 have?

x = 2 and y = 0

I will solve your system by substitution.

(You can also solve this system by elimination.) 3x - y = 6; 3x + y = 6 Step: 1

Solve 3x - y = 6 for y: 3x - y + - 3x = 6 + - 3x (Add - 3x to both sides) - y = - 3x + 6 - y - 1 = - 3x + 6 - 1 (Divide both sides by - 1) y = 3x - 6 Step 2:

Substitute 3x - 6 foryin 3x + y = 6 : 3x + y = 6 3x + 3x - 6 = 6 6x - 6 = 6 (Simplify both sides of the equation) 6x - 6 + 6 = 6+6 (Add 6 to both sides) 6x = 12 6x 6 = 126 (Divide both sides by 6) x=2 Step 3: Substitute2forxin y = 3x - 6 : y = 3x - 6 y = (3) (2) - 6 y=0 (Simplify both sides of the equation) Answer: x=2 and y=0