For the function f (t) = Pe^rt, if P = 6 and r = 0.06, then what is the value of f (6) to the nearest tenth? A. 219.6 B. 8.6 C. 0.1 D. 2.2

Question

Mathematics

Vanessa Byrd

14 July, 04:31

For the function f (t) = Pe^rt, if P = 6 and r = 0.06, then what is the value of f (6) to the nearest tenth? A. 219.6 B. 8.6 C. 0.1 D. 2.2

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Edward · Answer 1

B. 8.6 Let's substitute the given values into the function and calculate the result. So: f (t) = Pe^rt f (t) = 6e^0.06t f (6) = 6e^ (0.06*6) f (6) = 6e^ (0.36) f (6) = 6*1.433329415 f (6) = 8.599976487 Rounding to the nearest tenth, gives: 8.6 So the answer is "B. 8.6"