Ask Question
17 February, 13:50

One of the dog treats in Shelley's shop is 8 inches long and 3.2 inches wide. She wants to make a miniature version that has proportional dimensions. If the miniature treat will be 3 inches long, how wide should it be? 1.2 inches 1.8 inches 2.3 inches 3.2 inches

+4
Answers (1)
  1. 17 February, 16:25
    0
    Given:

    Original dog treat: 8 inches long, 3.2 inches wide.

    Miniature dog treat: 3 inches long,? wide

    We simply do cross multiplication of its proportion:

    Length to its width.

    Original treat: 8/3.2

    Miniature treat: 3/x

    8/3.2 = 3/x

    Cross multiply:

    8 * x = 3.2 * 3

    8x = 9.6

    Find the value of x

    x = 9.6/8

    x = 1.2

    The width of the miniature dog treat is 1.2 inches.

    To check:

    original treat: 8/3.2 = 2.5

    miniature treat: 3/1.2 = 2.5

    or:

    8/3.2 = 3/1.2

    8 * 1.2 = 3.2 * 3

    9.6 = 9.6
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “One of the dog treats in Shelley's shop is 8 inches long and 3.2 inches wide. She wants to make a miniature version that has proportional ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers