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30 May, 01:53

A basketball is thrown with an initial upward velocity of 25 feet per second from a height of 8 feet above the ground. The equation h=-16 t 2 + 25t+8 h=-16t2+25t+8 models the height in feet t seconds after it is thrown. After the ball passes its maximum height, it comes down and then goes into the hoop at a height of 10 feet above the ground. About how long after it was thrown does it go into the hoop?

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  1. 30 May, 02:39
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    -16t^2 + 25t + 8 = 10

    -16t^2 + 25t - 2 = 0

    t = 1.48 seconds
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