Find the area of a parallelogram with sides of 6 and 12 and an angle of 60°.

A: 72√3 sq. units

B: 36√3 sq. units

C: 12√3 sq. units

I think I got it. Correct me if I am wrong.

Parallelogram diagram I believe down below. We must find the height and then the area using Pythagorean theorem. Since the green shaded part is a 30-60-90 triangle, the base is 1/2 the hypotenuse, therefore it is 3. Now we calculate the height with it.

A^2 + B^2 = C^2

A^2 + 3^2 = 6^2

A^2 + 9 = 36

A^2 = 27

A = 3√3

Therefore the height is 3√3

Now calculate the area using A = bh

A = bh

= (12) (3√3)

= 36√3

So the area is 36√3 square units.

I cannot be sure of this answer because you did not provide a diagram.