Solve 3x2 + 13x = 10

a. x = two over three and x = - 5

b. x = 3 and x = - 3

c. x = - 2 and x = five over three

d. x = - 7 and x = 13

We want to solve the quadratic equation 3x² + 13x = 10.

Write the equation as

3x² + 13x - 10 = 0

Use the quadratic formula to obtain

x = (1/6) [ - 13 + / - √{13² - 4*3 * (-10) } ]

= (1/6) [-13 + / - √289]

= (1/6) [-13 + / - 17]

x = - 30/6 = - 5

or

x = 4/6 = 2/3

The solution is x = 2/3 and - 5.

Answer: a