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4 September, 15:15

A photograph has a length that is 6 inches longer than its width, x. So its area is given by the expression x (x+6) square inches. If the area of the photograph is 112 square inches, what is the width of the photograph?

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  1. 4 September, 15:52
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    112 = x (x + 6)

    112 = x^2 + 6x

    x^2 + 6x - 112 = 0

    (x - 8) (x + 14) = 0

    x - 8 = 0

    x = 8

    x + 14 = 0

    x = - 14 ... not this one because it is negative

    x = 8 <===width = 8 inches

    L = x + 6

    L = 8 + 6

    L = 14 ... length = 14
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