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18 March, 08:32

Katherine wants to construct a small box with a volume of 20 cubic inches with the following specifications. The length of a box is five more than its width. Its depth is one less than its width. What are the dimensions of the box in simplest radical form and rounded to the nearest hundredth? Only and algebraic solution will receive full credit.

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  1. 18 March, 10:02
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    V=LWH=20

    L is 5 more than W

    V=5+W

    H is 1 less than W

    H=-1+W

    easy, sub 5+W for L and - 1+W for H in LWH=V=20

    20 = (5+W) (W) (-1+W)

    expand

    20=W^3+4W^2-5W

    minus 20 both sides

    W^3+4W^2-5W-20=0

    either factor or graph to find the possible values for W

    (W+4) (W^2-5) = 0

    set each to zero

    W+4=0

    W=-4

    impossible, measures cannot be negative

    W^2-5=0

    add 5

    W^2=5

    sqrt both sides

    W=√5

    sub back

    L=5+W

    L=5+√5

    aprox

    7.24 rounded

    H=-1+W

    H=-1+√5

    aprox

    1.24 rounded

    the dimentions are

    √5 by (5+√5) by (-1+√5) or aprox

    2.24in by 7.24in by 1.24in
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