At forrest

elementary (k-5) 5/12 of the students are fourth and Fifth graders. There are 300 more k-3 students than fourth and Fifth graders. a. How many total students are at the school. b. Of the fourth graders and Fifth graders 2/5 are fourth graders. HOw many Fifth graders are there.

Let the number of 4th and 5th graders be x.

The number of k-3 graders will be (x+300)

The fraction of 4th and 5th graders is 5/12

The fraction of the whole students combined is 1/1

The fraction of k-3 graders is 1-5/12=7/12

The total number of students will be x + (x+300) = 2x+300

the fraction of 4th and 5th graders will be given by:

x / (2x+300) = 5/12

12x=5 (2x+300)

12x=10x+1500

2x=1500

x=1500/2=750

Thus the total number of students will be:

2x+300

=2*750+300

=1500+300

=1800

b] Given that of the 4th and 5th graders, (x=750), 2/5 are 4th graders, therefore the fraction of 5th graders will be:

1-2/5=3/5

the total number of 5th graders will be:

3/5*750

=450

The number of 5th graders will be 450