There are 3 quarters, 4 dimes and 7 nickels in a change purse. Suppose 3 coins are selected without replacement. What is the probability of selecting a quarter, then a dime, and then a nickel?

Question

Mathematics

Cassie Robinson

24 January, 17:46

There are 3 quarters, 4 dimes and 7 nickels in a change purse. Suppose 3 coins are selected without replacement. What is the probability of selecting a quarter, then a dime, and then a nickel?

+3

Answers (2)

Know the Answer?

Ryder Decker · Answer 1

Prob of just quarter is 3/14 for a dime is 4/14 and for a nickel its 7/14

then all you do is multiply them all together to get 306122449 / 10000000000 that took me way to long

Damarion Sandoval · Answer 2

0.037%

How I did it:

I did 3/13, and got 0.23, I didn't do 14 because if its going to be chosen, its going to have one less, and I did the same for the other ones. Then I simply just multiplied them.