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27 February, 22:34

From the top of a vertical tower 248 m high, a stone is projected vertically downwards with a speed of 8 ms. After x seconds another stone is projected vertically upwards from the level of the base of the tower with a speed 25 ms. Given that two stones are at same height moving in the same direction 6 seconds after projection of the first stone, calculate:

1) value of x

2) the velocity of the second stone at this instant

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  1. 28 February, 00:34
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    It is 2 that what i got and i think i got it write if not delete
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