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18 October, 02:03

For simple harmonic motion equation d=9cos (pi/2t) what is the frequency

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Answers (2)
  1. 18 October, 02:35
    0
    For this case we have an equation of the form:

    d = Rcos (wt)

    Where,

    R: amplitude

    w: angular frequency

    We have the following equation:

    d = 9cos (pi / 2t)

    The frequency is:

    w = pi / 2

    Answer:

    the frequency is:

    w = pi / 2
  2. 18 October, 04:37
    0
    On apex the answer is 1/4
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