Ask Question
16 September, 07:13

The law of cosines is a2+b2 - 2abcosC = c^2 find the value of 2abcosC ... A. 40 B. - 40 C. 37 D. 20

(The sides are 2,4, and 5; A to B is 2, B to C is 4, and A to C is 5.)

+1
Answers (1)
  1. 16 September, 10:58
    0
    A² + b² - 2abcosC = c²

    Аngle C lies opposite to the side AB, so "c" in the formula it is AB in your triangle

    4² + 5² - 2abcosC = 2²

    16 + 25 - 2abcosC = 4

    41 - 4 = 2abcosC

    2abcosC = 37
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The law of cosines is a2+b2 - 2abcosC = c^2 find the value of 2abcosC ... A. 40 B. - 40 C. 37 D. 20 (The sides are 2,4, and 5; A to B is 2, ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers