Suppose That the length of a certain rectangular is 1 meter more than 5 times it width. The perimeter of rectangular is 98 meters. Find the length and width

Let breadth (b) of rectangular be x

Then length (l) = 5x + 1

We have : perimeter (p) = 2 (l+b)

Or, p = 2 (5x+1+x)

p = 2 (6x + 1)

p = 12x + 2

Given that p = 98 m

98=12x+2 i. e. x = 8

So breadth b = 8m and length l = 5*8+1 = 41m