City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was - 3° C. What was the temperature of City A and City B on that day?

Your answer:

City A was 5° C, and City B was 4° C.

City A was 3° C, and City B was - 1° C.

City A was 8° C, and City B was - 3° C.

City A was 5° C, and City B was - 5° C.

Question

Mathematics

Quintin

22 December, 02:08

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was - 3° C. What was the temperature of City A and City B on that day?

Your answer:

City A was 5° C, and City B was 4° C.

City A was 3° C, and City B was - 1° C.

City A was 8° C, and City B was - 3° C.

City A was 5° C, and City B was - 5° C.

+1

Answers (1)

Know the Answer?

Terry Tucker · Answer 1

City A = x

City B = y

1st equation: 4x-8 = 3y

2nd equation: x-2y = - 3, rewrite as x = 2y-3

replace x in eq. 1 with equation 2

4 (2y-3) - 8 = 3y

8y-12-8=3y

8y-20 = 3y

-20 = - 5y

y = - 20/-5 = 4

x = 2y-3 = 2 (4) - 3 = 5

City A was 5° C, and City B was 4° C.