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7 February, 02:52

Assume that 2 cards are drawn in succession and without replacement from an ordinary deck of 52 cards. Find the probability that the following occurs.

1 diamond and 1 jack other than the jack of diamonds (in that order) are drawn

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  1. 7 February, 05:54
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    52 cards / 4 suites = 13 cards per suite

    4 Jacks total; 1 jack per suite

    Chance of drawing a diamond on the first draw: 13/52

    Without replacement means once drawn the card is not put back into the pool of cards. So the total cards, suit and type/number all decreases by one.

    Chance of drawing one of the 3 non-Diamond Jacks on second draw: 3/51

    Chance of drawing Diamond then non-Diamond Jack: (13/52) * (3/51) = 39/2652 = 0.015 (rounded to 1,000s place)
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