The means and mean absolute deviations of monthly snowfall during the winter months in two cities are shown in the table below.

Means and Mean Absolute Deviations of Snowfall in North Town and South Town

North Town South Town

Mean 8.9 in. 6.3 in.

Mean Absolute Deviation

0.55 in. 0.48 in.

The difference of the means is found and then compared to each of the mean absolute deviations. Which is true?

A) The difference between the means is about equal to the mean absolute deviation of the data sets.

B) The difference between the mean is about 2 times the mean absolute deviation of the data sets.

C) The difference between the mean is about 4 times the mean absolute deviation of the data sets.

D) The difference between the means is about 5 times the mean absolute deviation of the data sets.

Question

Mathematics

Karma

3 December, 05:57

The means and mean absolute deviations of monthly snowfall during the winter months in two cities are shown in the table below.

Means and Mean Absolute Deviations of Snowfall in North Town and South Town

North Town South Town

Mean 8.9 in. 6.3 in.

Mean Absolute Deviation

0.55 in. 0.48 in.

The difference of the means is found and then compared to each of the mean absolute deviations. Which is true?

A) The difference between the means is about equal to the mean absolute deviation of the data sets.

B) The difference between the mean is about 2 times the mean absolute deviation of the data sets.

C) The difference between the mean is about 4 times the mean absolute deviation of the data sets.

D) The difference between the means is about 5 times the mean absolute deviation of the data sets.

+5

Answers (1)

Know the Answer?

Makaila Ho · Answer 1

I believe the answer is D. The difference between the means is about 5 times the mean absolute deviation of the data sets. This is because 8.9-6.3 = 2.6 and 0.55*5 = 2.75 which is around 2.6. Also, 0.48*5 = 2.4 which is also around 2.6. This is the closest you can get to 2.6. By multiplying both of the MADs by 5.