The length of a rectangular poster is 7 inches more than twice its width. Find the length of the poster if its perimeter is 110 inches.

Let W = width of poster

Since the length is 7 inches longer than the width, the length is represented by W + 7.

We know the perimeter is equal to twice the length + twice the width and that is 110 inches. Mathematically that looks like:

2 (W + 7) + 2 (W) = 110

Now let's solve for W:

2 (w+7) + 2w=110

Step 1: Simplify both sides of the equation.

2 (w+7) + 2w=110

Simplify: (see simplify steps down below)

4w+14=110

Step 2: Subtract 14 from both sides.

4w+14-14=110-14

4w=96

Step 3: Divide both sides by 4.

4w4=964

w=24

Answer:

w=24

Simplify Steps:

(2) (w) + (2) (7) + 2w=110 (Distribute)

2w+14+2w=110

(2w+2w) + (14) = 110 (Combine Like Terms)

4w+14=110