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29 September, 16:35

Assume the substance has a half-life of 11 years and the initial amount is 126 grams. How long will it be until only 15 % remains?

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  1. 29 September, 19:44
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    (126) times (1/2 to the x/11 power) = 15% times 126

    (1/2) to the x/11 power = 0.15

    Take the log of both sides:

    (x/11) times log (1/2) = log (0.15)

    Multiply both sides by 11:

    'x' times log (1/2) = 11 x log (0.15)

    Divide both sides by " log (1/2) ":

    x = 11 x log (0.15) / log (1/2) = 30.107 years (rounded)

    That's the time it takes for any-size sample of this substance

    to decay to 15% of its original size.
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