Find four consecutive natural numbers if you know that the product of the first two is 38 less than the product of the following two numbers.

Because the four numbers are consecutive, we can call the first one x, and the other three are x+1, x+2, and x+3, respectively. x * (x+1) = (x+2) * (x+3) - 38 x^2 + x = x^2 + 5x + 6-38 x^2 + x = x^2 + 5x - 32 - 4x = - 32 x=8 The four numbers are 8, 9, 10, and 11 check solution: 8*9=10*11-38 72=110-38 72=72