If f (x) = 2-X1/2 and g (x) = x^2-9, what is the domain of g (x) divided by f (x)

I'm assuming X1/2 is sqrt (x) = x^ (1/2) = x^.5

You have to rationalize the denominator of 2-x^.5 which means multiplying by the conjugate or (2+x^.5) / (2+x^.5) which has a value of 1, so you aren't changing the value at all.

The answer is

(3x^2 - x^2.5 - 9x^.5 - 18) / (4-x)

I think it isx1/2=x^2_9