Factor completely: x3 - x2y - xy2 + y3

X^3-x^2-xy^2+y^3

the first factor is (x+y)

dividing the polynomial by the factor we get:

(x^2-2xy+y^2)

factoring the above quadratic equation we get:

x (x-y) - y (x-y)

= (x-y) (x-y)

thus the answer is:

x^3-x^2-xy^2+y^3 = (x-y) (x-y) (x+y)