There are 3 consecutive positive integers. the product of the first and third integer is 6 more than 6 times the second integer. what is the smallest integer? answer

Question

Mathematics

Yael Barber

17 February, 16:41

There are 3 consecutive positive integers. the product of the first and third integer is 6 more than 6 times the second integer. what is the smallest integer? answer

+4

Answers (1)

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Valeria Rice · Answer 1

Let the three integers be x - 1 x and x + 1

(x - 1) (x + 1) = 6x + 6

x^2 - 1 = 6x + 6

x^2 - 6x - 7 = 0

(x - 7) (x + 1) = 0

x - 7 = 0

x = 7

x + 1 = 0

x = - 1

the solutions are (7,0) and (-1,0)