Find four consecutive even integers such that if the sum of the first and the third is multiplied by 5 the result is 12 less than 9 times the fourth

4 consecutive even integers ... x, x + 2, x + 4, x + 6

5 (x + x + 4) = 9 (x + 6) - 12

5 (2x + 4) = 9x + 54 - 12

10x + 20 = 9x + 42

10x - 9x = 42 - 20

x = 22

x + 2 = 22 + 2 = 24

x + 4 = 22 + 4 = 26

x + 6 = 22 + 6 = 28

so ur numbers are : 22,24,26, and 28