A contractor digs a rectangular hole that is 40 feet long and 10.5 feet deep. If the contractor digs the hole 2 feet deeper, how much additional dirt will he remove

Question

Mathematics

Thomas Melendez

22 March, 11:07

A contractor digs a rectangular hole that is 40 feet long and 10.5 feet deep. If the contractor digs the hole 2 feet deeper, how much additional dirt will he remove

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Answers (1)

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Nathaly Romero · Answer 1

2 feet is the hight/depth

volume=legnth times wdth times height

if he digs 2 feet more, he will dig 2 height

assuming the hole is the same width and legtn

volume of dirt taken out mre=40*10.5*2=840 ft^2