One zero of x3 - 3x2 - 6x + 8 = 0 is - 2. What are the other zeros of the function?

Consider this solution, if it is possible, check the result:

1) if to divide polynomial 'x³-3x²-6x+8' on 'x+2' result is: x²-5x+4, then x³-3x²-6x+8 = (x+2) (x²-5x+4);

2) x²-5x+4 = (x-1) (x-4), then

3) x³-3x²-6x+8 = (x+2) (x-1) (x-4).

4) zeros are: - 2; 1; 4. Other zeros are: 1 and 4.

Answer: 1; 4.