If f (x) = 4x - 3, what is (f^-1 o f) (10) ?

F (x) = (4x-3) ^-1 (10))

(-4x+3 (10))

(-4x (30))

i think that's how you would solve it i can't quite remember if you substitute the x with the 10 but if you do it would be

f (x) = 4 (10) - 3

40-3

37

but im pretty sure it's the first way.