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6 September, 06:05

Prove that (n+5) ^2 (n+3) ^2 is a multiply of 4

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  1. 6 September, 09:28
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    Solve for n:

    (n + 3) ^2 (n + 5) ^2 = 0

    Split into two equations:

    (n + 3) ^2 = 0 or (n + 5) ^2 = 0

    Take the square root of both sides:

    n + 3 = 0 or (n + 5) ^2 = 0

    Subtract 3 from both sides:

    n = - 3 or (n + 5) ^2 = 0

    Take the square root of both sides:

    n = - 3 or n + 5 = 0

    Subtract 5 from both sides:

    Answer: n = - 3 or n = - 5 thus the Answer is wrong, neither - 3 or - 5 are a multiple of 4
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